Question

A vessel has 6 gram of oxygen at a pressure p and temperature 400 kelvin a small hole is made in it so "brainly"

Answer 1

The question is incomplete.

The complete question should be

A vessel has 6 gram of oxygen at a pressure p and temperature 400 kelvin a small hole is made in it so that oxygen leaks out. How much oxygen leaks out if pressure is p/2 and temperature 300 K.

Answer: -

Here P 1 = P

T 1 = 400 K

T 2 = 300 K

P 2 =P / 2

V is constant.

By ideal gas equation, P 1 x V = n1 x R x T 1

Again by ideal gas equation, P 2 x V = n2 x R x T 2

$\frac{n1}{n2}$ = $\frac{P 1 x T 2}{P 2 x T 1}$

= $\frac{P x 300}{P/ 2 x 400}$

= 1.5

Mass m 1 = 6 g.

Molar mass of oxygen gas = 32 g/ mol

Now

n 1 = $\frac{Mass}{Molar mass}$ = $\frac{6 g}{32 g / mol}$

Similarly

n 2 = $\frac{Mass}{Molar mass}$ = $\frac{m g}{32 g / mol}$

But $\frac{n 1}{n 2}$ = 1.5

$\frac{6/32}{m / 32}$ = 1.5

m 2 = 4 g

Here m 2 = mass of oxygen left.

Thus mass of oxygen leaked out = m 1 - m 2

= 6 - 4 = 2 g

Thus 2 g of oxygen gas leaked out.

Answer 2

Answer:

2 gm of O2 is leaked out.

Explanation:

Refer to the attached photo.

Hope this helps . :)