Question

A vessel has 60 L of solution of acid and
water having 80% acid. How much water is
to be added to make it solution in which acid
forms 60%?
(a) 48L
(C) 36L
(b) 20L
(d) None of these​

Answer 1

Step-by-step explanation:

60L has 48L acid and 12L water.

In first case, acid: water= 80:20 or 4:1 or 12:3 (for convenience)

In second case, acid: water=60:40 or 3:2 or 12:8 (for convenience).

Since, 12 units × 4 = 48L acid,

Thus, 5(=8–3) units × 4 = 20L of water to be added.