Question

A vessel has a gas at constant
temperature T and pressure 50cm of Hg.
If the vessel is divided into three equal
parts and the gas in the central part is
completely transferred to the other sides
equally, the pressure on either side is
(A) 75 cm
(B) 62 cm
(C) 54 cm
(D) 46 cm​

Answer 1

Answer:

C) 54 cm is answer dear friend

Answer 2

Answer:

The pressure on the either side is 75 cm of Hg.

Explanation:

Recall the Ideal gas law:

The volume of a given amount of gas is directly proportional to the number of moles of gas, directly proportional to the temperature and inversely proportional to the pressure. Symbolically,

V ∝ nT/P

⇒ V = nRT/P, where R is the ideal gas constant.

⇒ PV = nRT ...... (1)

Given: Initial volume, V = v

Initial pressure, P = 50 cm of Hg

Let n is the number of moles of gas

Since temperature is constant,

Substitute the values in (1), we get

⇒ 50v = nRT ...... (2)

Now,

Vessel is divided into three equal parts.

So, new volume, V = v/3

Number of moles, n = n/2

From equation (1),

⇒ P(v/3) = nRT/2

⇒ 2Pv/3 = nRT ...... (3)

From equation (2) and (3), we get

⇒ 50v = 2Pv/3

⇒ 50 × 3 = 2P

⇒ 150/2 = P

⇒ P = 75 cm

Therefore, the pressure on the either side is 75 cm of Hg.

SPJ3