A vessel has two equal compartments a and b containing h2 and o2 respectively each at 1 atm pressure if the wall separating the compartment is removed in pressure
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internal pressure of vessel
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Clearly , the pressure outside the vessel is 1 atm . ( Atmospheric pressure ! )
Also , each compartment separately has 1 atm pressure .
Let the volume of compartment A = Compartment B = X
When the separating wall is removed and we view the system of gases as the full container ,
the total volume of vessel = X + X = 2X
Also , by Dalton's law , we have ;
P ( vessel ) = P ( A ) + P ( B ) = 2 atm .
Hence , for 2X volume , we have the pressure 2 atm considering the vessel as a system .
Hence , the pressure in unit volume ( i.e. X ) , will be ( 2X / 2 ) = X
Hence , the pressure remains unchanged in both after removing wall .
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