Math, asked by shilpahindi, 2 months ago

A vessel having a volume of 3 liter it's length is 20 cm and breath is 15cm Find its height

Answers

Answered by dreamsatoz
0

Answer:

h×b×l=v

h×15×20=3

h=3/300

h=1/100

Answered by Yuseong
6

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Given Information :

• Volume of the vessel = 3 litre

• Length = 20 cm

• Breadth = 15 cm

To calculate :

• Height of the vessel.

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Clarification :

Here, we are given that the volume of the vessel is 3 litre and length and breadth of the vessel is 20 cm and 15 cm. We are asked to calculate the height of the vessel.

Vessel is in the shape of cuboid since it has different dimensions. We have to apply here the formula of volume of cuboid to find height. Before that, we'll convert volume into cubic cm as it is necessary to convert in cubic cm if we are given its length, breadth in cm. And, we'll find the height in cm.

Required Formula :

  • Volume of cuboid = l × b × h

So, let's commence the steps!

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Figure:

 \setlength{\unitlength}{0.74 cm}\begin{picture}\thicklines\put(5.6,5.4){\bf A}\put(11.1,5.4){\bf B}\put(11.2,9){\bf C}\put(5.3,8.6){\bf D}\put(3.3,10.2){\bf E}\put(3.3,7){\bf F}\put(9.25,10.35){\bf H}\put(9.35,7.35){\bf G}\put(3.5,6.1){\sf 15 \:cm}\put(7.7,6.3){\sf 20 \:cm}\put(11.3,7.45){\sf h \: }\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\end{picture}

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Explication of steps :

We have,

  • Length = 20 cm
  • Breadth = 15 cm
  • Volume = 3 litre

Converting volume into cm³ :

⇒ 1 litre = 1000 cm³

⇒ 3 litre = (3 × 1000) cm³

⇒ 3 litre = 3000 cm³

Henceforth, volume in cm³ is 3000 cm³.

Now, as we know that :

➝ Volume of vessel = Length × Breadth × Height

Substituting the values we have,

➝ 3000 cm³ = 20 cm × 15 cm × Height

➝ 3000 cm³ = 300 cm² × Height

 \sf { \cancel{\dfrac{3000 \: cm^3}{300 \: cm^2}} } = Height

 \underline { \boxed{ \sf { 10 \; cm = Height }}} \; \bigstar \\

Therefore, height of the vessel is 10 cm.

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