Question

a vessel in the form of an inverted cone . its height is 11cm radius of its top which is open is 2.5 cm. when spherical leads each of radius 0.5 cm are dropped in the vessel. two fifth of the water of vessel comes out. find the number of leads. plz fast.

Answer 1

Answer:

55

Step-by-step explanation:

Given A vessel in the form of an inverted cone . its height is 11cm radius of its top which is open is 2.5 cm. when spherical leads each of radius 0.5 cm are dropped in the vessel. two fifth of the water of vessel comes out. find the number of leads.

We have radius = 2.5 cm

height = 11 cm

So v = 1/3 π r^2 h

       = 1/3 π x 2.5^2 x 11

  Now when radius =  0.5 cm

 it will be 4/3 π 0.5^3 cm^3

Let the lead shots dropped into the vessel be S

So volume of S  lead shot = amount of water flowing = 2/5 volume of vessel.

S x 4/3 π(0.5)^3 = 2/5 x π/3 x (2.5)^2 x 11

0.5 S = 27.5

 S = 27.5/0.5

S = 55

So number of leads will be 55