A vessel in the form of an inverted cone. Its height is 8 cm and the radius of its top which is open is 5 cm. It is filled with water up to the brim. When lead shots each of which is a sphere of raduis 0.5 cm are dropped into the vessel, one-fourth of the water flows out. Find the number of lead shots dropped in the vessel.
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firstly, the volume of cone= 1/3 ×πr^2 × h
ie. v= 1/3 ×22/7 ×5×5×8 = 440/21 cm^3
after dropping some lead shots , the flowing water quality= 1/4 × 440/21 =110/21 cm^3
let the number of lead shots are 'n'
so volume of all lead shots= n× 4/3 × 22/7 × 0.5×0.5×0.5=. 88×0.125n/21
now volume of dropped water = volume of all lead shot
so, 110/21= 88×0.125n/21
therefore, n= 10
ie. v= 1/3 ×22/7 ×5×5×8 = 440/21 cm^3
after dropping some lead shots , the flowing water quality= 1/4 × 440/21 =110/21 cm^3
let the number of lead shots are 'n'
so volume of all lead shots= n× 4/3 × 22/7 × 0.5×0.5×0.5=. 88×0.125n/21
now volume of dropped water = volume of all lead shot
so, 110/21= 88×0.125n/21
therefore, n= 10
vishal6012:
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