Question

A vessel in the shape of cuboid contains some water if three identical spheres are immersed in the water the level of water is increased by 2 cm if the area of the base of the cuboid is 160 cm square and its height 12cm determine the radius of any of the spheres

Answer 1

Hey mate ^_^

=======
Answer:
=======

Area of the base of the cuboid = $160 {}^{2}$

Let the radius of the sphere be r cm.

Volume of one sphere = $4/3πr{}^{3}$

Volume of three spheres = $4πr{}^{3}$

Increased height of the cuboidal vessel = 2 cm

Increased volume of the water = $(160 × 2)cm{}^{3}$

= $320 cm{}^{3}$

Since the volume is increased after immersing the 3 spheres in the vessel,

So,

Increased volume of water = Volume of three spheres.

$4πr{}^{3} = 320$

$r{}^{3} = 320 / 4π$

$r{}^{3} = 320 / 4× 22/7$

$r{}^{3} = 320 × 7 / 4 ×22$

$r{}^{3} = 25.45$

$r = 2.94 cm$

Thus, the radius of the spheres is 2.94cm.

#Be Brainly❤️

Answer 2

the answer is r=2.94cm