Question

A vessel is filled with an ideal gas at a pressure of 10atm and temp 27degrees. Half of mass of gas is removed

Answer 1

Pressure will reduce to half on removing the half of the mass of gas.It us because pressure of a gas is directly proportional to mass of the gas.

Answer 2

Ideal gas equation, P₁V₁/n₁T₁ = P₂V₂/n₂T₂............A

Here, P₁= 10 atm

T₁ = 27° = (27+273) K = 300 K

T₂ = 87° = (87+273) K = 360 K

Now, M₁ = d x V₁ & M₂ = d x V₂

⇒ (M₁/V₁) = (M₂/V₂)

or, (M₁/V₁) = [(M₁/2)/V₂]

or, V₂ = V₁/2

or, V₁ = 2 V₂

thus, equation A can be written as,

(10 X  2 V₂) / 300 = (P₂ X V₂) / 360

or, P₂ = (360 X 20) / 300

or, P₂ = 24

Therefore the final pressure is 24 atm.