Question

. A vessel is filled with two different liquids which do not mix. One liquid is 40 cm deep and has n1= 1.6
and the other is 30 cm deep and has n2 = 1.5. What is the apparent depth of the vessel when viewed along
the normal?​

Answer 1

Answer:

70cm

Explanation:

When viewed along the normal there is no refraction taking place

Answer 2

Given : Two different liquids which do not mix

.            Depth of first liquid = 40cm,n1 = 1.6

            Depth of second liquid = 30cm, n2 = 1.6

To Find : Apparent depth of the vessel when viewed along

               the normal.

Solution :

When viewed across the normal, there will be no refraction

Thus,

Apparent depth of the vessel when viewed along the normal is equal to actual depth

Actual Depth = Depth of first liquid + Depth of second liquid

Actual Depth = 40cm + 30 cm = 70cm

Apparent depth = actual depth = 70cm.

Hence apparent depth when viewed along  the normal is 70cm.