Question

A vessel is in the form of a hemispherical bowl surmounted by hollow cylinder of same diameter. The diameter of hemi spherical bowl is 14 cm and total height of vessel is 13 cm. Find the total surface area of the vessel. (Use 7 22 π  ) CBSE2013-3M

Answer 1

I hope it will help you.

Answer 2

The total surface area of the vessel is 726 sq.cm.

Step-by-step explanation:

Diameter of hemisphere = Diameter of cylinder = 14 cm

Radius of hemisphere = radius of cylinder = $\frac{14}{2}=7 cm$

Height of vessel = 13 cm

Height of cylinder = height of vessel - radius of hemisphere = 13- 7 = 6 cm

Surface area of vessel = Surface area of cylinder + One base + Surface area of hemisphere

Surface area of vessel = $2 \pi r h + \pi r^2 + 2 \pi r^2$

Surface area of vessel =$2 \pi r h + 3 \pi r^2$

Surface area of vessel =$2 \times \frac{22}{7} \times 7 \times 6 + 3 \times \frac{22}{7} \times 7^2= 726 sq.cm.$

Hence the total surface area of the vessel is 726 sq.cm.

#Learn more:

A solid is in the form of a cylinder with hemispherical ends. The total height of the solid is 19cm and the diameter of the cylinder is 7 cm . Find the volume and total surface area of the solid .( use π=22/7)

https://brainly.in/question/2286081