Question

a vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. the diameter of the hemisphere is 14cm and the total height of the vessel is 13cm find the inner surface area of the vessel​

Answer 1

Answer:

Step-by-step explanation:

Radius of cylinder Andy hemisphere is 7cm

Height of the vessel is 13cm

Height of cylinder is 13-7 = 6cm

Inner surface area of vessel = CSA oF cylinder + CSA of hemisphere

= 2πrh + 2πr^2

= 2πr(h+r)

= 2 * 22/7 * 7(8+7)

=44*13

= 572sq.cm

(Refer attachment for diagram)

Answer 2

Answer:

Step-by-step explanation:

Given :-

Height of hemispherical part = Radius =7 cm

Height of cylindrical part (h) = 13 − 7 = 6 cm

To Find :-

Inner surface area of vessel

Formula to be used :-

Inner surface are of vessel = CSA of (cylindrical part + hemispherical part)

Inner surface are of vessel = $\bf 2\pi rh+2\pi r^2$

Solution :-

Putting all the values,we get

Inner surface are of vessel = $\bf 2\pi rh+2\pi r^2$

Inner surface are of vessel = $\sf 2\times\frac{22}{7}\times7\times6+2\times\frac{22}{7}\times7\times7$

Inner surface are of vessel = $\sf 44\times13$

Inner surface are of vessel = $\bf 572 \: cm^2$

Hence, The Inner surface are of vessel is $\bf 572 \: cm^2$