A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. Th
diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm Find this
inner surface area of the vessel.
Answers
Answered by
4
HERE ITS YOUR ANSWER
D of hemisphere = 14cm
r = 14/2 = 7cm
CSA of hemisphere = 2πr²
= 2 x 22/7 x 7 x 7 = 44x7
= 308cm²
r = 7cm
h(total) = 13cm
h(cylinder) = 13 - radius of heisphere = 13-7 = 6cm
CSA of Cylinder = 2πrh = 2 x 22/7 x 7 x 6
= 44x6 = 264cm²
Surface area of the vessel = CSA of Hemisphere + CSA of Cyclinder
= 308+264 = 572cm²
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D of hemisphere = 14cm
r = 14/2 = 7cm
CSA of hemisphere = 2πr²
= 2 x 22/7 x 7 x 7 = 44x7
= 308cm²
r = 7cm
h(total) = 13cm
h(cylinder) = 13 - radius of heisphere = 13-7 = 6cm
CSA of Cylinder = 2πrh = 2 x 22/7 x 7 x 6
= 44x6 = 264cm²
Surface area of the vessel = CSA of Hemisphere + CSA of Cyclinder
= 308+264 = 572cm²
mark as brainliest!!! CHeers!!
Read more on Brainly.in - https://brainly.in/question/2547273#readmore
Answered by
2
Now, the given parameters are:
The diameter of the hemisphere = D = 14 cm
The radius of the hemisphere = r = 7 cm
Also, the height of the cylinder = h = (13-7) = 6 cm
And, the radius of the hollow hemisphere = 7 cm
Now, the inner surface area of the vessel = CSA of the cylindrical part + CSA of hemispherical part
(2πrh+2πr2) cm2 = 2πr(h+r) cm2
2×(22/7)×7(6+7) cm2 = 572 cm2
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