A vessel is in the form of an inverted cone is filled with water to the brim its height is 20cm and diameter is 16.8cm. Two equal solid cones are dropped in it so that they are fully submerged. As a result one third of the water in the original cone over flows. What is the volume of each of the solid cones submerged?
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Answered by
1
Answer:
Step-by-step explanation:
Volume of inverted cone =1/3πr2h
Height of the cone = 20 cm
diameter = 16.8 cm
radius = 16.8/2 = 8.4 cm.
Volume of water in bigger cone = 1/3 πr2h = (1/3)x(22/7)x(8.4)x(8.4)x(20)
= 1478.4 cm3.
Volume of water overflowed = (1/3)(1478.4) = 492.8 cm3
Therefore Volume of each solid cone = (1/2)(492.8) = 246.4 cm3.
Answered by
1
Step-by-step explanation:
SIMPLY THANK ME AND MARK AS........
ANSWER
Volume of inverted cone =
3
1
πr
2
h
=
3
1
π(
2
16.8
)
2
×20
V=
3
1
π(8.4)
2
×20
when 2 similar cones are dropped one third of V is displaced
Volume of 2 cones =
3
1
× volume of inverted cone
3
V
=2× (volume of immersed cone)
∴ volume of each immersed cone =
3
1
×
3
1
π(8.4)
2
×20
=246.4cm
3
Volume of each immersed cone is 246.4cm
3
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