Question

A vessel is in the form of hemispherical bowl surmounted by a hollow cylinder the diameter of the hemisphere is 21 cm and the total height of the vessel is 14.5 cm find the capacity​

Answer 1

$\purple{\bold{\underline{\underline{Question:-}}}}$

A vessel is in the form of hemispherical bowl surmounted by a hollow cylinder the diameter of the hemisphere is 21 cm and the total height of the vessel is 14.5 cm find the capacity.

$\purple{\bold{\underline{\underline{Answer:-}}}}$

The diameter of the hemisphere is 21 cm and the total height of the vessel is 14.5. Height of the cylinder = Height of the vessel - Radius of the hemisphere . Therefore the total capacity of the vessel is 3808.035 cm³

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Answer 2

Answer:

Let the radius and height of cylinder be r cm and h cm respectively.

Diameter of the hemispherical bowl = 14 cm .

Therefore , Radius of hemispherical bowl = Radius of cylinder = r

$= > \frac{14}{2} cm = 7 \:cm \:$

Total height of the vessel = 13 cm

Therefore, the height of the cylinder , h = 13 cm - 7 cm = 6cm .

Total Surface area of the vessel = 2 ( Curved surface area of The Cylinder + Curved Surface area of the hemisphere.)

(Since , the vessel is hollow)

$= > 2(2 \: \pi \: r \: h \: + 2 \: \pi \: r \: {}^{2} ) \\ = 4 \: \pi \: r \: (h + r) = 4 \times \frac{22}{7} \times 7 \times (6 + 7) \: cm \: {}^{2}$

= 1144 cm 2