Question

a vessel of 100 cm square cross sectional area contains water the mass of water is 2 kg find the pressure acting on the bottom surface

Answer 1

Answer:

The pressure acting on the bottom surface is 19.6 Pa.

Explanation:

Given that,

Area = 100 cm²

Mass = 2 kg

The pressure is the force upon area.

The pressure  acting on the bottom surface  is define as:

$P = \dfrac{F}{A}$

$P = \dfrac{mg}{A}$

$P=\dfrac{2\times9.8}{100\times10^{-2}}$

$P= 19.6 Pa$

Hence, The pressure acting on the bottom surface is 19.6 Pa.

Answer 2

Answer:

Pressure, P = 1960 pascals

Explanation:

Given that,

Mass of water, m = 2 kg

Area of the square vessel, $A=100\ cm^2=0.01\ m^2$

Let P is the pressure acting on the bottom surface. It can be calculated as :

$P=\dfrac{F}{A}$

Since, F = mg

$P=\dfrac{mg}{A}$

$P=\dfrac{2\ kg\times 9.8\ m/s^2}{0.01\ m^2}$

P = 1960 pascals

So, the pressure acting on the bottom surface is 1960 pascals. Hence, this is the required solution.