Question

A vessel of 120 ml capacity contains a certain amount of gas at 35 degree C and 1.2 bar pressure . The gas is transferred to another vessel of volume 180 ml at 35 degree C . What would be it's pressure ?

Answer 1

according to boyle's law p1v1=p2v2
120×1.2=x×180
120×180. 2/180
=0.8

Answer 2

Hi 

Here is your answer,

p₁=1.2 bar 
p₂= ? 
V₁= 120 mL 
V₂= 180 mL 

 According to Boyle's law p₁V₁=p₂V₂

p₂= p₁V₁/V₂= 1.2 bar× 120mL/ 180mL = p₂ = 0.8 bar 

Hope it helps you!