Question

A vessel of 120 ml capacity contains a certain amount of gas at 35 degree celsius and 1.2 bar pressure the gas is transferred to another vessel of volume 180 ml at 35 degree celsius what would be its pressure

Answer 1

Hello
Given:
P1=1.2 bar
V1=120 ml
V2 =180 ml
Using boyle's law:
P1V1=P2V2
or
P2 = 0.8 bar

Answer 2

Hello!!

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$\Huge{\mathfrak{\blue{\underline{ANSWER}}}}$

Initial pressure, P1 = 1.2 bar

Initial volume, V1 = 120 mL

Final volume, V2 = 180 mL

As the temperature remains same, final pressure (P2) can be calculated with the help of Boyle’s law.

According to the Boyle’s law,

P1V1 = P2V2

P2 = P1V1 ÷ V2

= 1.2×120/180

= 0.8 bar

Therefore, the min pressure required is 0.8 bar.

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Thanks!!