Question

A vessel of 120 mL capacity contains amount of gas at 35 degree Celsius and 1.2 bar pressure.The gas is transferred to another vessel of volume 180 ml at 35 degree Celsius. What would be it's pressure? ​

Answer 1

Given:
P1=1.2 bar
V1=120 ml
V2 =180 ml
Using boyle's law:
P1V1=P2V2
P2 = 0.8 bar

Answer 2

$\huge\mathfrak{Solution}$

Given that :

P1 = 1.2 bar

P2 = ?

V1 = 120 mL

V2 = 180 mL

Here temperature is constant so according to Boyle's Law ,

P1V1 = P2V2

P2 = P1V1/V2

P2 = 1.2(bar) * 120(mL) / 180(mL)

P2 = 0.8 bar.

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