Question

A vessel of 120mL capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180mL at 35°C. What would be its pressure

Answer 1

0•8 Bar is a answerrrrer

Answer 2

Hello!!

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$\Huge{\mathfrak{\blue{\underline{ANSWER}}}}$

Initial pressure, P1 = 1.2 bar

Initial volume, V1 = 120 mL

Final volume, V2 = 180 mL

As the temperature remains same, final pressure (P2) can be calculated with the help of Boyle’s law.

According to the Boyle’s law,

P1V1 = P2V2

P2 = P1V1 ÷ V2

= 1.2×120/180

= 0.8 bar

Therefore, the min pressure required is 0.8 bar.

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Thanks!!