Question

A vessel of 125ml capacity contains a certain mass of gas at 25 degree celsius and 700 mm of pressure the gas was transferred to vessel whose volume is 175 ml Calculate the pressure of gas at 25degree celsius?

Answer 1

use

p1v1=p2v2

P2=p1v1/V2

=700*125/175

=500 mm of pressure

Answer 2

Answer:

P₂ = 500 mm

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,  

V₁ = 125 mL

V₂ = 175 mL

P₁ = 700 mm

P₂ = ?

T₁ = T₂ = 25 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = T₂ = (25 + 273.15) K = 298.15 K  

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{700}\times {125}}{298.15}=\frac {{P_2}\times {175}}{298.15}$

Solving for P₂ , we get:

P₂ = 500 mm