Chemistry, asked by shreyaskasturethegre, 10 months ago

A vessel of 25 L contains 20 g of ideal gas X at 300 K. The pressure eas 20 g of ideal gas X at 300 K. The pressure exerted by the gas is 1 atm. 20 g of idealgas Y is added to the vessel keeping the same temperature. Total preser keeping the same temperature. Total pressure became 3 atm. Upon furtheraddition of 20 g ideal gas Z the presurre became 7 atm. Answer the following questionsequation is applicable on mixture of ideal gases)[Take R = 1/12 L.atm/mol K]5. Find the molar mass of gas X:(A) 20 g(B) 10 g(C) 30 g(D) 5g& Identify the correct statement(s):1.gas Y is lighter than gas XII. gas Z is lighter than gas Y(A) I only(B)ll only(C) Both I and II(D) None of the statementsFind the average molar mass of the mixture of gases X,Y and Z:(A) 40/7(B) 50/7(C) 20(D) 60/7​

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Answered by Chetan43555
1

Answer:

don't know yaar ..

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Answered by rchauhanskr
0

Explanation:

I don't know the answer

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