Question

A vessel of 5litre of capacity maintained 27ºc was filled with 16g of o2 gas calculate the pressure of the gas atmosphere in the container.

Answer 1

Answer:volume of gas=volume of cylinder

V=5 lite

T=27°C=27+273=300K

given mass(m)=16g

molar mass of O2=32g

n=mM=16/32=1/2mol

pressure(P)=?

applying ideal gas equation

PV=nRT

P=nRT/v

=0.5×0.0821×300/5

=2.46 atm

Answer 2

Answer:

2.46 atm

Explanation:

Given:

• Volume = 5 litre
• Given mass of oxygen = 16 g
• Temperature = 27°C

To find:

• Pressure of gas in atm in the container.

Solution:

Firstly, let us change temperature in kelvin as the SI unit of temperature is Kelvin.

→ 27°C + 273

→ 300 K

For moles,

n = given mass/molar mass

→ n = 16/32

→ n = 0.5

We know that,

PV = nRT

(That is ideal gas equation)

Putting the values we get,

→ P × 5 = 0.5 × 0.0821 × 300

→ P × 5 = 12.31

→ P = 12.31/5

→ P = 2.46 atm

Hence, pressure of gas (O2) will be 2.46 atm.