Question

A vessel of capacity 600 cm cube contains hydrogen gas at a pressure of 330 cm what will be the pressure of hydrogen gas when the vessel is connected to another vessel of 300 cm cube capacity

Answer 1

The answer in the book is wrong

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Answer 2

Answer:

220

Explanation:

Given A vessel of capacity 600 cm cube contains hydrogen gas at a pressure of 330 cm what will be the pressure of hydrogen gas when the vessel is connected to another vessel of 300 cm cube capacity

According to Boyle’s law the equation is

P1V1 = P2V2

P1 = initial pressure = 330

V1 = initial volume = 600 cm^3

P2 = final pressure

V2 = final volume = (600 + 300) cm^3 = 900 cm^3

Substituting the given values we get

330 x 600 = P2 x 900

P2 = 330 x 600 / 900

P2 = 220 cm

So the final pressure will be 220 cm