Question

A vessel of capacity 600cm3 contains hydrogen gas at a pressure of 304 cm Hg. What will be the pressure of hydrogen gas, when the vessel is connected to another vessel of 300 cm3 capacity?

Answer 1

P¹= 304 Hg
V¹= 600cm³
V²= 600+ 300= 900cm³
P²=?
P¹V¹= P²V²
P²= P¹V¹/V²
P²= 600×304/900
P²= 202.67 cm of Hg

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Answer 2

Hey mate here is your answer

P1=304 Hg
V1=600 cm cube
V3=600+300=900 cm cube
P2v2=p1v1/v2=p2=600*304/900
02=202.67 cm Hg

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