Question

A vessel of capacity 600cm3 contains hydrogen gas at a pressure of 304 cm Hg. What will be the pressure of hydrogen gas, when the vessel is connected to another vessel of 300 cm3 capacity?
Ans is given:202.67cm of Hg

Answer 1

P¹= 304 Hg V¹= 600cm³ V²= 600+ 300= 900cm³ P²=? P¹V¹= P²V² P²= P¹V¹/V² P²= 600×304/900 P²= 202.67 cm of Hg

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Answer 2

Answer: 202.67 cm Hg

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure of gas= 304 cm Hg

$V_1$ =  initial volume of gas = $600cm^3$

$P_2$ = final pressure of gas= ?

$V_2$ = final volume of gas = $(600+300)cm^3=900cm^3$

Putting values in above equation, we get:

$304\times 600=P_2\times 900$

$P_2=202.67cmHg$

Thus the final pressure will be 202.67 cm Hg