Question

a vessel of certain 600 cm cube contains hydrogen gas at a pressure of 330 cm what will be the pressure of hydrogen gas when the vessel is connected to another version of 300 cm cube capacity ​

Answer 1

Answer:

Answer: P¹= 304 Hg V¹= 600cm³ V²= 600+ 300= 900cm³ P²=? ... gas, when the vessel is connected to another vessel of 300 cm3 capacity? Ans is given:202.67cm of Hg

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Answer 2

Answer:

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1 = initial pressure of gas= 304 cm Hg

V_1 = initial volume of gas = 600cm^3

P_2 = final pressure of gas= ?

V_2 = final volume of gas = (600+300)cm^3=900cm^3

Putting values in above equation, we get:

304\times 600=P_2\times 900

P_2=202.67cmHg