A vessel of depth 'd'is half filled with a liquid of refractive index py and the other half is filled with a liquid of refractive index ji2. The apparent depth of
the vessel, when looked at normally, is
(A) d(ui + M2)
(B) d (1+
H2
(C) (un + m2)
(D) (+)
Answers
Answered by
0
Correct option is
B
d(
μ
1
1
+
μ
2
1
)
Apparent depth =
refractive index
real depth
⇒ depth seen =
μ
1
d
+
μ
2
d
=d(
μ
1
1
+
μ
2
1
)
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