Physics, asked by manchaladavidkevin, 8 hours ago

A vessel of depth 'd'is half filled with a liquid of refractive index py and the other half is filled with a liquid of refractive index ji2. The apparent depth of
the vessel, when looked at normally, is
(A) d(ui + M2)
(B) d (1+
H2
(C) (un + m2)
(D) (+)​

Answers

Answered by janu6469
0

Correct option is

B

d(

μ

1

1

+

μ

2

1

)

Apparent depth =

refractive index

real depth

⇒ depth seen =

μ

1

d

+

μ

2

d

=d(

μ

1

1

+

μ

2

1

)

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