a vessel of heat capacity 420 joule per gram contain 500 gram of water at 40 degree Celsius. Steam at hundred degree celsius is allowed to condense In The vessel. What quantity of steam is required to reach the water to its boiling point. specific latent heat of steam is equal to 2200 J/g
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Answered by
1
Answer:
i littel confusee at your question
Answered by
1
Answer:
68.72 gram
Explanation:
According to the principle of calorimetry,
Heat lost by steam=Heat gained by water+Heat gained by vessel
m×2200=500×4.2×(100-40)+420×(100-40)
2200m=126000+25200
2200m=151200
m=151200÷2200
=68.72 gram
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