Question

A vessel of volume 0.02m³ contain a mixture of hydrogen and helium at 20°C and 2 atm pressure . The mass of a mixture is 5gms . Find the ratio of mass of hydrogen to that of helium in the mixture?

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Answer 1

ANSWER

From ideal gas equation PV=nRT,

Here, assume mass of helium in mixture

is x, then mass of hydrogen is (5-x) so,

2×10 ^5

× 0.02=( ( 5−x ) / 2 + x/4 ) 8.314 × 293.

x=3.43 and 5 − x = 1.57

So ratio of hydrogen to helium is 1:2.

then x+ y = 3

Related info -

A vessel of volume 0.02m3 contains a mixture of hydrogen and helium at 20∘C and 2 atmospheric pressure. The mass of mixture is 5 gms

Answer 2

Answer:

From ideal gas equation PV=nRT,

Here, assume mass of helium in mixture is x, then mass of hydrogen is (5-x) so, 2×10

5

×0.02=((5−x)/2+x/4)8.314×293.

x=3.43and5−x=1.57.

So ratio of hydrogen to helium is 1:2.

then x+ y = 3