Physics, asked by kashafkashu9, 6 months ago

A vessel of volume 'V' is half - filled with a liquid “A” of volume coefficient of expansion a1 and the other half with a liquid B of volume coefficient a2 at
00C. If the vessel has negligible coefficient of expansion, the mass of liquid that over flows when it heated to 100C is (density of A = d, density of B =
0.8d)
(A) Vd(a1+a2)
(B) 4Vd(a1+a2)
(C) 4Vd [(a 1+a2)2]
(D) 4Vd(a1-a2)​

Answers

Answered by baljinderkaur586945
0

Explanation:

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Answered by talasilavijaya
0

Answer:

Mass of liquid that is overflown is 4Vd(a_{1}+a_{2})

Explanation:

Given volume of liquid A =  volume of liquid B = \frac{V}{2}

          volume coefficient of expansion of liquid A is a_{1}

          volume coefficient of expansion of liquid B is a_{2}  

          Temperature difference, \Delta T=10^{o} C

          density of liquid A =d

          density of liquid B, \rho = 0.8d

Volume expansion is

                       \Delta V=\rho V_{0} \Delta T

                       \Delta V=a_{1}  \times \frac{V}{2} \times 10+a_{2} \times \frac{V}{2} \times 10

                              =5V(a_{1}+a_{2})

As density of liquid B is less, it is lighter than A and hence overflows after expansion.

Mass of the liquid overflown is m=\rho\Delta V

                          m=0.8d \times 5V(a_{1}+a_{2})

                               =4Vd(a_{1}+a_{2})

Mass of liquid B that is overflown is 4Vd(a_{1}+a_{2})

So, the correct is option B.

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