Physics, asked by mamtaraj979, 1 year ago

A vessel with water is placed on a weighing pan and reads 600 g. Now a ball of 40 g and density 0.80 g/cc is sunk into the water with a pin as shown in fig., ke

Answers

Answered by Fatimakincsem
0

The weighing pan will show a reading of 650 g.

Explanation:

Upthrust on ball = weight of displaced water

                          = Vσg

                          = (m/ρ)σg  

                          = 40/0.8 × 1 × g = 50 g

As the ball is sunk into the water with a pin by applying downward force equal to upthrust on it. Therefore, reading of weighing pan

R  = weight of water + downward f (D)

R =  600 + 50 = 650 g

The weighing pan will show a reading of 650 g.

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