Question

a vessels contain 48 l mixture of milk and water in which milk is 3 times more than water. 10 l of mixture is taken out and 20 l of pure water added in it what is the difference between the quantity of milk and water in the final mixture​

Answer 1

Answer:

Let the initial quantity of the mixture is x.

Milk in initial mixture = 10/(10+3) * x = 10x/13

Milk taken out = 26 * 10/13 = 20 lit

Since, after taking out 26 lit mixture, only water is added, there is no change in remaining milk quangity.

Remaining milk = 10x/13 - 20

Volume of final solution = x- 26 + 10 = x - 16

By the given condition

(10x/13 - 20) / ( x - 16 ) = 5/(5+2)

Or, 70x/13 -140 = 5x - 80

Or, 70x/13 - 5x = 140 -80 = 60

Or, 5x/13 = 60 or, x = 13 * 60/5 = 156 litres

So,initial quantity of mixture = 156 litres Ans