Math, asked by luthra4841, 1 year ago

A veterinarian surveys 26 of his patrons. He discovers that 14 have dogs, 10 have cats, and 5 have fish. Four have dogs and cats, 3 have dogs and fish, and one has a cat and fish. If no one has all three kinds of pets, how many patrons have none of these pets?

Answers

Answered by TooFree
50

Answer:

5 of them do not have any pets


Step-by-step explanation:

Total number of patrons = 26


Total number of patrons that have dogs = 14

Total number of patrons that have cats = 10

Total number of patrons that have fish = 5


Total number of patrons that have dogs and cats = 4

Total number of patrons that have dogs and fish = 3

Total number of patrons that have cats and fish = 1


Total number of patrons that have all three pets = 0


Total number of patrons that have only dogs = 14 - 4 - 3 = 7

Total number of patrons that have only cats = 10 - 4 - 1 = 5

Total number of patrons that have only fish = 5 - 3 - 1 = 1


Total number of patrons that have none = 26 - 7 - 5 - 1 - 4 - 3- 1 = 5


Answer: There are 5 that have none have pets.





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Answered by shanicedsouza20
3

Below attached is ur answer

Hope this helps you

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