Question

A vibrating object complete 500 cycles in 10 seconds. Calculate its frequency and time
period.

Answer 1

Answer:

The frequency (f) of a wave is the number of full waveforms generated per second. This is the same as the number of repetitions per second or the number of oscillations per second.

Time Period (T) is the number of seconds per waveform or the number of seconds per oscillation. It is clear that frequency and period are reciprocals.

In this case, A tuning fork's tongs vibrate 250 times in 2.0 s.

That is, the frequency is given as f=

2

250

=125Hz.

Time period =

f

1

=

125

1

=8×10

−3

s.

Hence, the frequency is 125 Hz and the time period is 8×10

−3

s seconds.

Answer 2

Given : A vibrating object complete 500 cycles in 10 seconds.

　

To find : What is its time period and frequency?

　

Using formula :

1) Frequency = Number of times the pendulum oscillates/Total number of time taken.

　

2) Time period = Number of oscillation per second/Frequency.

　

Calculations :

→ Frequency = 500/10

→ Frequency = 50 hertz

　

→ Time period = 10/50

→ Time period = 0.2 seconds

　

Therefore,

1. Frequency = 50 hertz.
2. Time period = 0.2 seconds.