Question

a vibrating tuning fork has a frequency of 250 Hz. the distance between two consecutive compressions is 25cm. what is the velocity with which the wave is travelling forward?

Answer 1

Answer:

Wave Velocity(v) = Wave length(λ) * Frequency(f)

Given : Frequency = 250Hz

Wave length = 25cm

                     = 0.25m

Thus, v= 0.25m * 250Hz

            = 62.50m/s

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Answer 2

Given:

The frequency is 250 Hz

The distance is 25 cm= 0.25m

To find:

The velocity of the wave travelling forward

Solution:

The time period is

T=1/f

T=1/250

T=0.004 sec

The velocity of the wave is

v=d/T

putting above values

v=0.004/0.25

v=0.016 m/sec

The velocity of the wave travelling forward is the 0.016 m/sec