Question

A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes

Answer 1

Correct Answer:

4 s

Explanation:

Time period of a vibration magnetometer,

T 1 / √B

T₁ / T₂ = √(B₂ / B₁)

T₂ = T₁ √(B₁ / B₂)

2 √ (24 x 10⁻⁶ / 6 x 10⁻⁶) = 4 sec.