A vichle of 100 kg is moving with velocity of 5m/sec. To stop it in o.1 sec the required force in opposite direction is
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mass = m = 100kg
initial velocity = u = 5m/s
final velocity = v = 0m/s (at rest)
time = t = 0.1s
acceleration = a = ?
Force = F = ?
1)
a = v-u/t
a = 0-5/0.1
a = -5/0.1
a = -50m/s²
2)
F = ma
F = 100×-50
F = -5000kgm/s²
F = -5000N
F = -5KN (5 kilo newton)
(here - represent it is acting apposite to the motion of object)
so your answer is "-5000N" or "-5KN ".
initial velocity = u = 5m/s
final velocity = v = 0m/s (at rest)
time = t = 0.1s
acceleration = a = ?
Force = F = ?
1)
a = v-u/t
a = 0-5/0.1
a = -5/0.1
a = -50m/s²
2)
F = ma
F = 100×-50
F = -5000kgm/s²
F = -5000N
F = -5KN (5 kilo newton)
(here - represent it is acting apposite to the motion of object)
so your answer is "-5000N" or "-5KN ".
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