Question

A village having a population of 4000 requires 150 liters of water per head per day. It has a tank measuring 20 m x 15 m x 6 m. The water of this tank will last for

Answer 1

Answer:

Total water consumption in a day

$= 4000 \times 150 = 600000 \: l$

Volume of tank

$= 20 \times 15 \times 6 \: {m}^{3} \\ = 1800 \: {m}^{3} \\ since \: 1 {m}^{3} = 1000 \: l \\ = 1800000 \: l$

So water will last for

$= \frac{1800000}{600000} = 3 \: days$

Answer 2

Answer: 3 days

Step by step explanation:

Given,

Quantity of water in tank = (20 ×15×6) = 1800m³

Population of village = 4000

Water required = 150/per head per day              

Quantity of water required by the village per day:

                                    = ( 4000 × 150) liters

                                    = 4000×150 ÷ 1000 m³

                                    =  600 m³

No. of days which the water will last

                                   = 1800÷600

                                   = 3 days

Explanation:

This question can be solved by 2 methods, I have solved this question in very simple way. In this question, There was the Given population and water requires per day.

And, There were a tank, which was wearing of 20 meters, 15 meters and 6 meters. We First find, Quantity of water in tank = (20 ×15×6) = 1800m³.

Then, We find Quantity of water required by the village per day.

= ( 4000 × 150) liters

= 4000×150 ÷ 1000 m³

= 600 m³.

And, Finally we divide it with 600 with 1800. And, we get 3 days.