Math, asked by shivamgeroh, 11 months ago

a village having a population of 4000 requires 150 litre water per head per day it has a trunk measuring 20 by 15 by 6 for how many days the water of these tank will last​

Answers

Answered by TigerMan28
5

Answer:3 days

Step-by-step explanation:

If the measurement of tank is given in m. Then,

Volume of tank=

20*15*6

1800m^3

Total amount of water available=

1800*1000. (1m^3=1000 litres)

18,00,000l

Water needed per day =

4000*150

6,00,000l

Day it will last=

1800000/6000000

3 days

Answered by Anonymous
0

Answer: 3 days

Step by step explanation:

Given,

Quantity of water in tank = (20 ×15×6) = 1800m³

Population of village = 4000

Water required = 150/per head per day              

Quantity of water required by the village per day

                                    = ( 4000 × 150) liters

                                    = 4000×150 ÷ 1000 m³

                                    =  600 m³

No. of days which the water will last

                              = 1800÷600

                              = 3 days

Explanation:

This question can be solved by 2 methods, I have solved this question in very simple way. In this question, There was the Given population and water requires per day.

And, There were a tank, which was wearing of 20 meters, 15 meters and 6 meters. We First find, Quantity of water in tank = (20 ×15×6) = 1800m³.

Then, We find Quantity of water required by the village per day.

= ( 4000 × 150) liters

= 4000×150 ÷ 1000 m³

= 600 m³.

And, Finally we divide it with 600 with 1800. And, we get 3 days.

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