Question

a village having a population of 4000 requires 150 litre of water per head per day it has a tank wearing 20 metre into 15 metre into 6 for how many days will the water of this tank last​

Answer 1

Answer: 3 days

Step by step explanation:

Given,

Quantity of water in tank = (20 ×15×6) = 1800m³

Population of village = 4000

Water required = 150/per head per day

                   

Quantity of water required by the village per day

                                     = ( 4000 × 150) liters

                                     = 4000×150 ÷ 1000 m³

                                     =  600 m³.

                             

No. of days which the water will last

                               = 1800÷600

                               = 3 days

                             

Explanation:

This question can be solved by 2 methods, I have solved this question in very simple way. In this question, There was the Given population and water requires per day.

And, There were a tank, which was wearing of 20 meters, 15 meters and 6 meters. We First find, Quantity of water in tank = (20 ×15×6) = 1800m³.

           

Then, We find Quantity of water required by the village per day

= ( 4000 × 150) liters

= 4000×150 ÷ 1000 m³

= 600 m³.

               

And, Finally we divide it with 600 with 1800. And, we get 3 days.

Answer 2

$\bf{ \underline{ \underline{Answer \: : }}} \:$

$\large\bold\red{Answer~is~3~days~.}$

$\bf{ \underline{ \underline{Explanation \: : }}}$

● Here we have to find volume of tank.

$= lbh \\ \\ = 20 \times 15 \times 6 \\ \\ = 1800 { \: m}^{3}$

$⟹1800 { \: m}^{3} = 1800 \times 1000 \\ \\ =1800000 \: l$

● Required water for 1 day :-

$= 4000 \times 150 \\ \\ = 600000 \: l$

● Tank contains 1800000 L in one time

● Required water for 1 day is 600000 L

● Days will thewater to this tank is :-

$= \frac{1800000 \: l}{600000 \: l} \\ \\ \bf{ \underline{ \underline{ \: = 3\: days }}}$

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