Math, asked by bhartisaroha, 1 year ago

a village having a population of 4000 requires 150 litres of water per head per day it has a tank measuring 20m multiply 15 m x 6 m the water of the tank will last for​

Answers

Answered by neilsequeira759
0

Answer:

Step-by-step explanation:

Volume (tank)= 20×16×6

=1920m^3

Total water required by village in 1 day= 4000×150

=600000litres

Therefore if

1m^3=1000litres

then 1920m^3=?

Capacity of water in tank =192000litres

Time taken for the tank to get empty= 600000÷192000=3.125 days

=3days approx or 3days s 3hours

Answered by Anonymous
0

Answer: 3 days

Step by step explanation:

Given,

Quantity of water in tank = (20 ×15×6) = 1800m³

Population of village = 4000

Water required = 150/per head per day              

Quantity of water required by the village per day:

                                   = ( 4000 × 150) liters

                                   = 4000×150 ÷ 1000 m³

                                   =  600 m³

No. of days which the water will last

                                  = 1800÷600

                                  = 3 days

Explanation:

This question can be solved by 2 methods, I have solved this question in very simple way. In this question, There was the Given population and water requires per day.

And, There were a tank, which was wearing of 20 meters, 15 meters and 6 meters. We First find, Quantity of water in tank = (20 ×15×6) = 1800m³.

Then, We find Quantity of water required by the village per day.

= ( 4000 × 150) liters

= 4000×150 ÷ 1000 m³

= 600 m³.

And, Finally we divide it with 600 with 1800. And, we get 3 days.

Similar questions