Question

A village having a population of 8000, requires 200 litres of water per day. It has a tank measuring 20m× 10× 8m. For how many days will the water of this tank last​

Answer 1

Answer:

8 days

Step-by-step explanation:

20×10×8 = 1600

1600÷200 = 8 days.

Answer 2

$\huge \colorbox{orange}{Question :-}$

⇒ A village having a population of 8000, requires 200 litres of water per day. It has a tank measuring 20m× 10× 8m. For how many days will the water of this tank last​ ?

$\huge \colorbox{orange}{Given :-}$

⇒ Total Population of the village = 8000

⇒ Water required per day = 200 l

⇒ Measure of the tank = 20m × 10m × 8m

$\huge \colorbox{orange}{To\: Find :-}$

⇒ For how many days will the water of that tank last​

$\huge \colorbox{orange}{Solution :-}$

⇒ $\sf No.\: of\: days\: water\: will \: last\: = \frac{Volume\: of\: tank}{Total\: Water\: Required\: Per \: Day}$

⇒ Here ,

l = 20 m

b = 10 m

h = 8 m

Volume of Tank = l × b × h

→ 20 m × 10 m × 8 m

→ 1600 m³

⇒ Water required by each person per day = 200 l

⇒ Water required by 8000 persons per day

→  $\sf 8000 \times 200 \times \frac{1}{1000}m^{3\\\\}$

→ $\sf 1600 m^{3}$

⇒ No. of days it will last

→ $\sf \frac{Volume\; of\; tank}{Total \; water \; required \; per \; day}$

→ $\sf = \frac{1600}{1600} \\\\= 1$

∴ It will last for 1 day.