Question

a village water tank contained some water. the villagers used 10 300 litres of water in the day. a pump then supplied 12 700 litres of water into the tank. there was 16 500 litres of water left in the tank in the end. how much water was there in the tank ar first?

Answer 1

x - 10300 + 12700 = 16500

x + 2400 = 16500

x = 16500 - 2400

x = 14100.

Answer 2

14,100 litres of water was there in the tank at first.

• Let the initial quantity of water contained in the tank be x.

• Given,

Quantity of water used by the villagers in a day = 10,300 l

Quantity of water now left in the tank = Initial quantity of water in the tank - Quantity of water used up by the villagers

=> Quantity of water left in the tank = x - 10,300 l

• Quantity of water re-supplied into the tank = 12,700 l

Quantity of water in the tank now = Quantity of water that was left + Quantity of water re-supplied into the tank

=> Final quantity of water in the tank = x - 10,300 l + 12,700 l

= x - 10,300 l + 12,700 l

= x + 2,400 l

• It is given that the quantity of water finally left in the tank = 16,500 l

∴   According to the question,

x + 2,400 l = 16,500 l

=> x = 16,500 l - 2,400 l

=> x = 14,100 l

∴   14,100 l of water was there in the tank initially.