Physics, asked by sarahriaz394, 9 months ago

A voltage divider circuit of two resistors is designed with a total resistance of the two resistors equal to 50.0 ohm. If the output voltage is 10 percent of the input voltage,obtain the values of the two resistors in the circuit.​

Answers

Answered by Anonymous
0

Answer:

Answer:The voltage divider is made of two resistors, so the "power of the divider" has to account for both. You can compute the power a few different ways. If you know the current i flowing through the two resistors, then p = i^2 (R1 + R2).

Answered by bharathparasad577
0

Answer:

Concept:

A substance's ability to obstruct the flow of electrical current is referred to as resistance. The capital letter R is used to symbolize it.

Explanation:

Given:

  • A voltage divider circuit of two resistors is designed with a total resistance of the two resistors equal to 50.0 ohm
  • The output voltage is 10 percent of the input voltage.

Find:

The values of the two resistors in the circuit.​

Solution:

Let the input voltage be V  and

Let the two resistors be R1 and R2

It is given that the output voltage is 10 percent of the input voltage.

Since, we have considered input voltage as V, output voltage = 0.1 V ---(1)

By voltage division rule, the voltage across R2 = \mathrm{V}_{0}=\frac{R_{2}}{R_{1}+R_{2}} -------(2)

Now, by comparing the two equations, we get

                           $$\begin{aligned}&\frac{R_{2}}{R_{1}+R_{2}} * V=0.1 * V \\&\frac{R_{2}}{50} * V=0.1 * V \\&R_{2}=5 \Omega\end{aligned}

So the value of 2nd resistor is 5 \Omega

     the value of 1st resistor is 50 - 5 = 45 \Omega

#SPJ3

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