Question

A voltage drop of 4V appears across a resistor of 100 ohm. What power is dissipated in the resistor?

Answer 1

$0.25 \: W$

Explanation:

$Given, \: V=4V \: \: and \: \: \: R=100 \:ohm \\ we \: \: know \: \: that \: \: \boxed{</p><p>P= \frac{ {V}^{2} }{R} } \\ Now, \: \: \: putting \: \: values \\ P= \frac{ {4}^{2} }{100} \\ = \frac{25}{100} \\ = 0.25 \: W$