Question

A voltage e(t)= 150sin100πt is applied to a series circuit consisting of 10ohm resistance, 0.318 henry inductance. Determine i) expression of current
ii) phase angle between voltage and current
iii) active power consumed
iv) peak value of pulsating energy

Answer 1

Answer:

According to the question V=200sin314t and R=10Ω

comaring it with original equation we get ,V

m

=200V

(1} rms voltage , V

rms

=

2

V

m

=0.707×200=141.4V

(2)rms current , I

rms

=

R

V

rms

=

10

141.4

=14.14A

(3)power dissipate ,P=V

rms

I

rms

cosθ

here cosθ is power factor which is equal to 1 for pure resistive circuit since voltage and current are in same phase,

p=141.4×14.14=1999.69≃2000W