Question

a voltage of 5 v is applied across a colour coded carbon resistor with first ,2,3 of brown , black and red. what is the current flowing through the resistor??​

Answer 1

the number for brown and black rings are 1 and 0 where is the multiplier factor for red is 10^2 .

R = 10 × 10^ 2 ohm

V = 5 V

current, I = V\R

= 5 \ 10× 10^2

= 5 × 10^-3 A

= 5 mA

Answer 2

$\huge\mathfrak\red{Hello}$

resistance of the resistor=10×10² ohm

voltage=5 v

so current=I=v÷R

=5 ÷ 10×10²= 5×10⁻³ A =5 mA

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