a voltage of 5V is applied across a colour coded carbon resistor with first, second and third rings of brown, black, and red colour.what is the current flowing through the resistor?
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resistance of the resistor=10×10² ohm
voltage=5 v
so current=I=v÷R
=5 ÷ 10×10²= 5×10⁻³ A =5 mA
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