A voltage V = 150 + j 180 is applied
across an impedance and the current
flowing is found to be 1 =5 - j 4. Determine
(i) scalar impedance (ii) resistance (iii)
reactance (iv) power consumed.
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Given : voltage V = 150 + j 180
I =5 - j 4.
To find : (i) scalar impedance (ii) resistance (iii) reactance
Solution :
V = I Z
Z = V/I
=> Z = (150 + j 180 )/(5 - j 4)
= (150 + j 180 )(5 + j 4) / (5 - j 4)(5 + j 4)
= {750 - 720 + j(900 + 600)} / (25 + 16)
= (1470 + j 1500)/49
Scaler impedance = √(1470)² + (1500)² / 49 = 2100/49 = 42.86 Ω
Resistance = 1470/49 = 30 Ω
Reactance = 30.61 Ω
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